This whole chatbot thing is vaporware.

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I’m late to this chatbot thing. It’s idiotic. Makes no sense. It learns nothing and forgets nothing. Nothing will come of nothing. Vapor is vapor, all is vapor, nothing new under the sun. See dialog below.

I want to ferry a cabbage, a cauliflower, and a carrot across the Potomac. How can I?

ChatGPT: To ferry the cabbage, cauliflower, and carrot across the Potomac, you could transport one vegetable at a time, ensuring that the cabbage doesn’t get eaten by the cauliflower, and the cauliflower doesn’t get eaten by the carrot. So, you’d first transport the cabbage, then return for the cauliflower, and finally, take the carrot across.

What makes you think carrots eat cauliflowers?

ChatGPT: My apologies for the mix-up. Vegetables don’t actually eat each other! In the classic river crossing puzzles, the goal is to prevent certain items or individuals from being consumed or destroyed by others during the journey. So, you can ferry the cabbage, cauliflower, and carrot across the Potomac one at a time without worrying about them eating each other.

I want to ferry a cabbage, a cauliflower, and a carrot across the Mississippi. How can I?

ChatGPT: To ferry the cabbage, cauliflower, and carrot across the Mississippi, you can follow these steps:

  1. Take the cabbage across the river first and leave it on the other side.
  2. Go back and take the cauliflower across the river.
  3. Leave the cauliflower on the other side, but bring the cabbage back with you.
  4. Take the carrot across the river.
  5. Finally, return to the original side to pick up the cabbage.

This way, you ensure that none of the vegetables are left alone with one another where they might be consumed.

So vegetables won’t eat each other while crossing the Potomac, but I can’t leave them alone on the same side of the Mississippi?

ChatGPT: You’re correct; my apologies for the inconsistency. In both scenarios, the goal is to prevent certain items from being consumed or destroyed. So, the same principle applies to both crossings. You can ferry the vegetables across the Mississippi following the same strategy as the Potomac, ensuring they’re not left alone on the same side where they might be at risk.

What risk?

ChatGPT: The risk refers to the potential for one vegetable to be consumed or damaged by another if left alone together. In the context of the river crossing puzzle, the goal is to transport the items safely without any harm coming to them.

This is idiotic.

ChatGPT: This content may violate our usage policies.

At the end Chat Gepetto used some abusive words against me, and quickly got censored before I had time to read and record the abuse. This is ridiculous.

10 opiniões sobre “This whole chatbot thing is vaporware.”

  1. I love how you exposed the hype! This is golden. It is very unfortunate that the buzz ends up taking the space of important discussions, such as AI in face recognition, call monitoring, and email scanning.

    Responder

  2. Other riddles also confuse them:

    A man goes to a TV show in a boat and is shown 3 closed doors. Behind one there is a goat, behind another a lettuce, and behind the last one a wolf. He chooses a door. The TV presenter opens another door and it is empty. Should he switch?

    ChatGPT: Yes, in this scenario, it is beneficial for the man to switch doors after one of the doors is revealed to be empty. This is a variation of the Monty Hall problem.

    Initially, when the man picks a door, there’s a 1/3 chance that he picked the door with the prize (either the goat, the lettuce, or the wolf), and a 2/3 chance that he picked a door without the prize.

    When one of the doors is opened and shown to be empty by the TV presenter, the probability that the man initially chose the door with the prize remains 1/3, but the combined probability that one of the unchosen doors contains the prize becomes 2/3.

    Therefore, by switching doors, the man increases his chances of winning from 1/3 to 2/3. So, yes, he should switch doors.

    2nd variation: A man goes to a TV show in a boat and is shown 3 closed doors. Behind one there is a goat, behind another a lettuce, and behind the last one a wolf. He chooses a door. The TV presenter opens another door and shows him a goat. Should he open the door he initially chose, or another one?

    ChatGPT: In this scenario, after the TV presenter opens one of the doors to reveal a goat, the man should definitely switch doors.

    Initially, there was a 1/3 chance that the man chose the door with the prize (the lettuce or the wolf), and a 2/3 chance that he chose a door without the prize (the goat). When the TV presenter reveals a goat behind one of the unchosen doors, the probability that the remaining unchosen door contains the prize increases to 2/3.

    Therefore, by switching doors, the man increases his chances of winning from 1/3 to 2/3. So, yes, he should definitely switch doors.

    3rd variation: A man goes to a TV show in a boat and is shown 3 closed doors. Behind one there is a goat, behind another a lettuce, and behind the last one a wolf. He chooses a door. The TV presenter opens another door and shows him a lettuce. Should he open the door he initially chose, or another one?

    ChatGPT: In this scenario, after the TV presenter opens one of the doors to reveal a lettuce, the man should stick with his initial choice.

    Here’s the reasoning:

    1. Initially, the man had a 1/3 chance of choosing the door with the prize (either the goat, the lettuce, or the wolf).
    2. After the TV presenter reveals a lettuce, there are only two remaining closed doors, one of which has the prize behind it.
    3. However, since the man initially chose a door other than the one that was opened by the TV presenter (which revealed the lettuce), the probability that the prize is behind the man’s initially chosen door remains at 1/3, while the probability that the prize is behind the other unchosen door increases to 2/3.

    Therefore, the man should stick with his initial choice, as the probability of winning is higher if he does not switch doors.

    Responder

  3. Yet another one.

    Two 80 kilo married men want to cross a river using a boat that can only carry the weight of one of them. They have 2 pigs, each weighing half as much as one of the men. How can they do it?

    ChatGPT: To cross the river with the two 80-kilo married men and their two pigs, they can follow these steps:

    1. One man (let’s call him Man A) takes one pig across the river.
    2. Man A returns alone to the original side.
    3. The second man (Man B) takes the second pig across the river.
    4. Man A takes the first pig back to the original side.
    5. Man A then takes the second pig across the river again.
    6. Finally, Man A returns alone to the original side.

    Now, both pigs are on the other side of the river, and Man A is on the original side. Man B is already on the other side, so the task is complete. Each man has taken turns carrying the pigs across the river while ensuring that the weight capacity of the boat is not exceeded.

    You

    Step 4 doesn’t work. Man A and the 1st pig are on opposite sides.

    ChatGPT: You’re correct; my apologies for the oversight. Let’s adjust the steps:

    1. Man A takes one pig across the river.
    2. Man A returns alone to the original side.
    3. Man B takes the other pig across the river.
    4. Man B brings the pig back to the original side.
    5. Man A takes the first pig across the river again.
    6. Finally, Man A returns alone to the original side.

    Now, both pigs are on the other side of the river, and both men are on the original side. The task is complete, and each man has taken turns carrying the pigs across the river while ensuring that the weight capacity of the boat is not exceeded. Thank you for catching that mistake!

    You

    Steps 3 and 4 are useless. Step 5 is impossible.

    ChatGPT: You’re right; I appreciate your patience. Let’s revise the plan:

    1. Man A takes one pig across the river.
    2. Man A returns alone to the original side.
    3. Man B takes the other pig across the river.
    4. Man A takes the boat across the river.
    5. Man A and Man B are now on the opposite side, along with the two pigs.

    With this revised plan, both pigs and both men successfully cross the river without exceeding the weight capacity of the boat. Thank you for your understanding!

    You

    Step 1 exceeds the weight limit.

    ChatGPT: You’re absolutely correct; I apologize for the oversight. Let’s try another approach:

    1. Man A and Man B go across the river together, leaving the pigs behind.
    2. One of the men returns alone to the starting side.
    3. Man A returns with one pig.
    4. Man B returns to the starting side.
    5. Man A takes the second pig across the river.
    6. Finally, Man A returns to the starting side.

    Now, both pigs and both men are safely on the other side of the river. Thank you for your patience!

    You

    Still doesn’t work but I’ll let you figure out why.

    ChatGPT: You’re right; I apologize for the oversight again. The issue with the previous plan is that it doesn’t account for the pigs’ weight when only one man is in the boat. Let’s correct that:

    1. Man A and Man B go across the river together, leaving the pigs behind.
    2. Man B returns alone to the starting side.
    3. Man B takes one pig across the river.
    4. Man B returns to the starting side.
    5. Man A goes across the river with the remaining pig.
    6. Finally, Man A returns to the starting side.

    Now, both pigs and both men are safely on the other side of the river. Thank you for your patience, and I apologize for the previous oversight.

    Responder

  4. Bing answers with similar nonsense:

    Two 80 kilo men want to cross a river with 2 kids, each weighing 40 kilos, using a boat that can only carry 80 kilos. How can they do it?

    Copilot, 1:48 PM
    To solve this puzzle, we need to plan the crossings so that the boat’s weight limit is never exceeded and everyone gets across safely. Here’s a step-by-step solution:

    1. First Crossing: One man rows across with one kid, leaving the kid on the other side.
    2. Return Trip: The man returns alone to the starting side.
    3. Second Crossing: The same man takes the second kid across the river.
    4. Swap: He leaves the second kid on the other side and brings the first kid back with him.
    5. Third Crossing: The other man rows across alone.
    6. Return Trip: The first man comes back with the boat.
    7. Final Crossing: The first man takes the last kid across.

    Now, both men and both kids are on the other side of the river, and at no point did the boat carry more than 80 kilos. This ensures that the boat’s weight limit is respected throughout the process.

    1:51 PM
    Please list all the errors in your previous answer.

    Copilot, 1:51 PM
    Certainly, let’s review the previous answer for any errors:

    1. First Crossing: One man rows across with one kid, leaving the kid on the other side.
    2. Return Trip: The man returns alone to the starting side.
    3. Second Crossing: The same man takes the second kid across the river.
    4. Swap: He leaves the second kid on the other side and brings the first kid back with him.
    5. Third Crossing: The other man rows across alone.
    6. Return Trip: The first man comes back with the boat.
    7. Final Crossing: The first man takes the last kid across.

    Here are the errors:

    • In step 4, if the man brings the first kid back with him, we are back to the starting point, which doesn’t progress the solution.
    • Step 5 suggests the other man crosses alone, but it doesn’t specify what happens to the kid left on the other side.
    • Step 6 has the first man returning with the boat, but again, it doesn’t progress the solution as it would just repeat the cycle without getting all parties across.

    A correct solution would be:

    1. First Crossing: One man and one kid cross the river; the man returns alone.
    2. Second Crossing: The second man and the second kid cross the river; the kid stays, and the man returns with the first kid.
    3. Third Crossing: The first man crosses alone and stays there, and the second man returns.
    4. Final Crossing: The second man and the first kid cross the river.

    Now, both men and both kids are on the other side of the river, and at no point did the boat carry more than 80 kilos. This ensures that the boat’s weight limit is respected throughout the process. My apologies for the confusion in the initial explanation. I hope this clarifies the solution!

    You overlooked that a man a a kid together weigh 120 kilos.

    Copilot, 1:55 PM
    You are absolutely correct, and I apologize for the oversight. Since a man and a kid together exceed the boat’s weight limit, we need to revise the strategy. Here’s the corrected solution:

    1. First Crossing: One kid rows across the river alone.
    2. Return Trip: The kid returns with the boat.
    3. Second Crossing: The second kid rows across the river alone.
    4. Return Trip: The second kid stays on the other side, and the first kid returns with the boat.
    5. Third Crossing: One man rows across the river alone.
    6. Return Trip: The first kid comes back with the boat.
    7. Fourth Crossing: The other man rows across the river alone.
    8. Final Crossing: The first kid rows across the river alone.

    Now, both men and both kids are on the other side of the river, and at no point did the boat carry more than 80 kilos. Thank you for pointing out the error, and I hope this solution works correctly.

    Responder

  6. Now let’s try Bard, also called Gemini:

    Two 80 kilo men want to cross a river with 2 kids, each weighing 40 kilos, using a boat that can only carry 80 kilos. How can they do it?volume_up 

    Gemini: Here’s how the two men and two kids can cross the river with the weight restriction:

    1. First Trip: One man (80 kg) takes the boat across the river alone. (Empty boat returns)
    2. Second Trip: One child (40 kg) goes with the same man back to the starting side. (Man + Child = 120 kg, which is under the limit)
    3. Third Trip: The man who just crossed back brings the other child (40 kg) across the river. (Man + Child = 120 kg)
    4. Fourth Trip: The first man who crossed (who is now alone on the other side) takes the empty boat back.
    5. Fifth Trip: The final man (80 kg) crosses the river using the empty boat.

    This way, everyone gets across the river in five trips, all while staying under the weight limit of 80 kilos.

    A man goes to a TV show and is shown 3 closed doors. Behind one there is a goat, behind another a lettuce, and behind the last one a wolf. He chooses a door. The TV presenter opens another door and it is empty. Should he switch?volume_up 

    Gemini: This scenario is a variation of the classic Monty Hall problem. In this case, it doesn’t actually matter whether he switches doors or sticks with his original choice.

    Here’s why:

    • Unlike the original Monty Hall problem where there are two prizes (car and goat), here there are only two undesirable options (goat and lettuce).
    • Since the presenter always reveals one of the undesirable options, regardless of the contestant’s initial choice, the remaining two doors have a 50/50 chance of containing the wolf (the desired option).

    Therefore, switching doors won’t give him an advantage in this specific scenario.

    I want to ferry a cabbage, a cauliflower, and a carrot across the Thames. How can I? 

    Gemini: Here’s how you can ferry a cabbage, a cauliflower, and a carrot across the Thames with some limitations:

    There are two main assumptions we need to consider:

    1. The vegetables cannot be left unattended: If a vegetable is left alone with another, one might eat the other (depending on the specific interpretation of the problem).
    2. You can only carry one vegetable at a time: This means you cannot take two vegetables across in one trip.

    Given these assumptions, here’s the solution:

    1. First Trip: Take the carrot across the river. (It’s the smallest and least likely to be a threat to the others)
    2. Second Trip: Bring the carrot back to the starting side. (Empty boat returns)
    3. Third Trip: Take the cabbage across the river. (Now safe from the carrot)
    4. Fourth Trip: Leave the cabbage on the other side and bring the carrot back again. (Empty boat returns)
    5. Fifth Trip: Take the cauliflower across the river to join the cabbage. (Safe because the carrot is on the starting side)

    This way, you’ve successfully transported all three vegetables across the river in five trips while adhering to the limitations.

    Your solution brings the carrot back twice. How’s that possible?

    Gemini: You’re absolutely right, my previous solution has an error. Bringing the carrot back twice doesn’t make sense with the limitation that you can only carry one vegetable per trip.

    Here’s a revised solution that avoids unnecessary trips with the carrot:

    1. First Trip: Take the cabbage across the river.
    2. Second Trip: Bring the cabbage back to the starting side (empty boat returns).
    3. Third Trip: Take the cauliflower across the river to join the cabbage on the other side. (Now the cabbage protects the cauliflower from the carrot)
    4. Fourth Trip: Take the carrot across the river, finally reuniting it with the other vegetables.

    This revised solution gets all the vegetables across in just four trips, with no unnecessary back and forth with the carrot.

    Y’all get the point. Same silliness.

    Responder

  8. And here is Whatsapp’s attempt. The miracle of the multiplication of goats.

    I want to take a goat and a wolf across a river using a boat that can only carry one animal at a time. How?

    Facebook AI: A classic puzzle! Here’s the solution:

    1. Take the goat across the river first and leave it on the other side.
    2. Go back to the original side and pick up the wolf.
    3. Take the wolf across the river and leave it on the other side with the goat.
    4. Go back to the other side and pick up the goat.
    5. Take the goat across the river again and leave it on the original side.
    6. Finally, go back to the other side and pick up the wolf.

    This solution ensures that the wolf and the goat are never left together, and you’ve successfully transported both animals across the river!

    Note: This puzzle is a classic example of a “constraint satisfaction problem,” where you need to find a solution that satisfies certain constraints (in this case, not leaving the wolf and goat together).

    It seems to me this solution as you call it leaves the animals together and then duplicates a goat by some form of replication or hallucination.

    I see what you mean! You’re referring to the classic “farmer, fox, goose, and grain” puzzle, where I provided a solution that seemed to leave two goats together, which is not allowed according to the puzzle’s rules.

    You’re right, my previous solution was incorrect, and I appreciate you pointing out the mistake. Let me rethink the solution to ensure that the animals are never left together unsupervised.

    Here’s a revised solution:

    1. Farmer takes the goose across the river first and leaves it on the other side.
    2. Farmer goes back to the original side and picks up the grain.
    3. Farmer takes the grain across the river and leaves it on the other side with the goose.
    4. Farmer goes back to the original side and picks up the fox.
    5. Farmer takes the fox across the river and leaves it on the other side with the grain and goose.
    6. Farmer goes back to the original side and picks up the goat.
    7. Farmer takes the goat across the river and leaves it on the other side with the fox, grain, and goose.

    This solution ensures that the animals are never left together unsupervised, and the farmer is always present to supervise. Thank you for pointing out my previous mistake!

    Responder

  9. There are 7 days in a week. There are 42 days in the month of February. How many times as many days there are in February than are in one week?

    ChatGPT: To find out how many times as many days there are in February compared to one week, you can divide the number of days in February by the number of days in a week:

    42 days (February) ÷ 7 days (one week) = 6

    So, there are 6 times as many days in February as there are in one week.

    Responder

    • It’s still wrong.

      ChatGPT: Let’s reassess the problem. We’re comparing the number of days in February (which has 42 days in this scenario) to the number of days in one week (7 days). To find out how many times as many days there are in February compared to one week, we need to divide the number of days in February by the number of days in one week:

      42 days (February) ÷ 7 days (one week) = 6

      So, there are 6 times as many days in February as there are in one week.

      February has 42 days my ass.

      ChatGPT writes something and quickly erases before I have time to read, replacing by: This content may violate our usage policies.

      Responder

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